Alphabetic Shift
Given a string, replace each its character by the next one in the English alphabet (z would be replaced by a).

Example

• For inputString = “crazy”, the output should be alphabeticShift(inputString) = “dsbaz”.
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function alphabeticShift(inputString) {
  const alphabet =  ['a', 'b' ,'c' ,'d', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n' ,'o' ,'p', 'q' ,'r' ,'s' ,'t' ,'u' ,'v' ,'w' ,'x' ,'y', 'z'];

  let inputShifted = inputString.split('');
  for(let i = 0; i< inputShifted.length;i++){
    let index = 0;

    if (inputShifted[i] !== 'z') {
      index = alphabet.indexOf(inputShifted[i]) + 1;
    }
    inputShifted[i] = alphabet[index]
  }
    return inputShifted.join('')
  }



console.log(alphabeticShift('crazy')); 4sbbaz

We create function called alphabeticShift with parameter inputString and local variable *inputShifted that is equal to inputString.split(‘’) and alphabet = [‘a’, ‘b’ ,’c’ ,’d’, ‘e’, ‘f’, ‘g’, ‘h’, ‘i’, ‘j’, ‘k’, ‘l’, ‘m’, ‘n’ ,’o’ ,’p’, ‘q’ ,’r’ ,’s’ ,’t’ ,’u’ ,’v’ ,’w’ ,’x’ ,’y’, ‘z’];

We loop through the InputShifted with for loop and decalare variable index = 0 other than that I check with if statement if inputShifted[i] !== ‘z’ then index = alphabet.indexOf(inputShifted[i]) + 1

Else we inputShifted[i] = alphabet[index]


In the end we inputShifted.join(‘’)